HackerRank-Aggregation-Top Earners

Top Earners

We define an employee’s total earnings to be their monthly salary x months worked, and the maximum total earnings to be the maximum total earnings for any employee in the Employee table. Write a query to find the maximum total earnings for all employees as well as the total number of employees who have maximum total earnings. Then print these values as 2 space-separated integers.

Input Format The Employee table containing employee data for a company is described as follows:

where employee_id is an employee’s ID number, name is their name, months is the total number of months they’ve been working for the company, and salary is the their monthly salary.

Sample Input

Sample Output

69952 1

Explanation

The table and earnings data is depicted in the following diagram:

The maximum earnings value is 69952. The only employee with earnings 69952 is Kimberly, so we print the maximum earnings value (69952) and a count of the number of employees who have earned 69952(which is 1) as two space-separated values.

My solution 1

SELECT max(earnings), count(earnings)
FROM
(
    SELECT salary*months as earnings, RANK() OVER(order by salary*months DESC) as rank
    FROM Employee
)
GROUP BY rank
HAVING rank=1;

My solution 2

SELECT *
FROM
(
SELECT salary*months as earnings, count(*)
FROM employee
GROUP BY salary*months
ORDER BY salary*months DESC
)
WHERE ROWNUM = 1;